Jeremy Cowles

2008-08-01 17:43:02 UTC

When it says ALUOp0 and ALUOp1, I made the assumption that this meant the

the 0 or 1 bit in the 2 bit ALUOp signal. So when the signal is stuck at

zero:

ALUOp0 >> ALUOp = x0

ALUOp1 >> ALUOp = 0x

And when it is stuck at 1:

ALUOp0 >> ALUOp = x1

ALUOp1 >> ALUOp = 1x

Where "x" is either 1 or 0 depending on the instruction. Is this correct?

Thanks,

Jeremy

the 0 or 1 bit in the 2 bit ALUOp signal. So when the signal is stuck at

zero:

ALUOp0 >> ALUOp = x0

ALUOp1 >> ALUOp = 0x

And when it is stuck at 1:

ALUOp0 >> ALUOp = x1

ALUOp1 >> ALUOp = 1x

Where "x" is either 1 or 0 depending on the instruction. Is this correct?

Thanks,

Jeremy