Jeremy Cowles
2008-08-01 17:43:02 UTC
When it says ALUOp0 and ALUOp1, I made the assumption that this meant the
the 0 or 1 bit in the 2 bit ALUOp signal. So when the signal is stuck at
zero:
ALUOp0 >> ALUOp = x0
ALUOp1 >> ALUOp = 0x
And when it is stuck at 1:
ALUOp0 >> ALUOp = x1
ALUOp1 >> ALUOp = 1x
Where "x" is either 1 or 0 depending on the instruction. Is this correct?
Thanks,
Jeremy
the 0 or 1 bit in the 2 bit ALUOp signal. So when the signal is stuck at
zero:
ALUOp0 >> ALUOp = x0
ALUOp1 >> ALUOp = 0x
And when it is stuck at 1:
ALUOp0 >> ALUOp = x1
ALUOp1 >> ALUOp = 1x
Where "x" is either 1 or 0 depending on the instruction. Is this correct?
Thanks,
Jeremy